Pierre bought some mangoes and starfruits in the ratio of 1 : 4 . After buying another 115 fruits each, the ratio becomes 8 : 9. Find the number of mangoes and starfruits he has now.
| |
Mangoes |
Starfruits |
Difference |
| Before |
1x1 =
1 u |
4x1 =
4 u |
3x1 =
3 u |
| Change |
+ 115 |
+ 115 |
|
| After |
8x3 =
24 u |
9x3 =
27 u |
1x3 =
3 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of mangoes and starfruits at first and in the end remains unchanged.
Make the difference in the number of mangoes and starfruits the same. LCM of 3 and 1 is 3.
Increase in the number of mangoes
= 24 u - 1 u
= 23 u
23 u = 115
1 u = 115 ÷ 23 = 5
Number of starfruits and mangoes that $(Fred) has now
= 24 u + 27 u
= 51 u
= 51 x 5
= 255
Answer(s): 255
