Gabriel bought some grapefruits and pomegranates in the ratio of 1 : 4 . After buying another 18 fruits each, the ratio becomes 5 : 11. Find the number of grapefruits and pomegranates he has now.
| |
Grapefruits |
Pomegranates |
Difference |
| Before |
1x2 =
2 u |
4x2 =
8 u |
3x2 =
6 u |
| Change |
+ 18 |
+ 18 |
|
| After |
5x1 =
5 u |
11x1 =
11 u |
6x1 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of grapefruits and pomegranates at first and in the end remains unchanged.
Make the difference in the number of grapefruits and pomegranates the same. LCM of 3 and 6 is 6.
Increase in the number of grapefruits
= 5 u - 2 u
= 3 u
3 u = 18
1 u = 18 ÷ 3 = 6
Number of pomegranates and grapefruits that $(Fred) has now
= 5 u + 11 u
= 16 u
= 16 x 6
= 96
Answer(s): 96
