Fred bought some grapefruits and mangoes in the ratio of 1 : 4 . After buying another 56 fruits each, the ratio becomes 5 : 12. Find the number of grapefruits and mangoes he has now.
| |
Grapefruits |
Mangoes |
Difference |
| Before |
1x7 =
7 u |
4x7 =
28 u |
3x7 =
21 u |
| Change |
+ 56 |
+ 56 |
|
| After |
5x3 =
15 u |
12x3 =
36 u |
7x3 =
21 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of grapefruits and mangoes at first and in the end remains unchanged.
Make the difference in the number of grapefruits and mangoes the same. LCM of 3 and 7 is 21.
Increase in the number of grapefruits
= 15 u - 7 u
= 8 u
8 u = 56
1 u = 56 ÷ 8 = 7
Number of mangoes and grapefruits that $(Fred) has now
= 15 u + 36 u
= 51 u
= 51 x 7
= 357
Answer(s): 357
