Seth bought some dragonfruits and persimmons in the ratio of 1 : 4 . After buying another 76 fruits each, the ratio becomes 7 : 9. Find the number of dragonfruits and persimmons he had at first.
| |
Dragonfruits |
Persimmons |
Difference |
| Before |
1x2 =
2 u |
4x2 =
8 u |
3x2 =
6 u |
| Change |
+ 76 |
+ 76 |
|
| After |
7x3 =
21 u |
9x3 =
27 u |
2x3 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of dragonfruits and persimmons at first and in the end remains unchanged.
Make the difference in the number of dragonfruits and persimmons the same. LCM of 3 and 2 is 6.
Increase in the number of dragonfruits
= 21 u - 2 u
= 19 u
19 u = 76
1 u = 76 ÷ 19 = 4
Number of persimmons and dragonfruits that Seth had at first
= 2 u + 8 u
= 10 u
= 10 x 4
= 40
Answer(s): 40
