Fred bought some dragonfruits and chikoos in the ratio of 1 : 3 . After buying another 30 fruits each, the ratio becomes 8 : 9. Find the number of dragonfruits and chikoos he had at first.
| |
Dragonfruits |
Chikoos |
Difference |
| Before |
1x1 =
1 u |
3x1 =
3 u |
2x1 =
2 u |
| Change |
+ 30 |
+ 30 |
|
| After |
8x2 =
16 u |
9x2 =
18 u |
1x2 =
2 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of dragonfruits and chikoos at first and in the end remains unchanged.
Make the difference in the number of dragonfruits and chikoos the same. LCM of 2 and 1 is 2.
Increase in the number of dragonfruits
= 16 u - 1 u
= 15 u
15 u = 30
1 u = 30 ÷ 15 = 2
Number of chikoos and dragonfruits that Fred had at first
= 1 u + 3 u
= 4 u
= 4 x 2
= 8
Answer(s): 8
