Paul bought some chikoos and grapefruits in the ratio of 1 : 5 . After buying another 39 fruits each, the ratio becomes 5 : 12. Find the number of chikoos and grapefruits he had at first.
| |
Chikoos |
Grapefruits |
Difference |
| Before |
1x7 =
7 u |
5x7 =
35 u |
4x7 =
28 u |
| Change |
+ 39 |
+ 39 |
|
| After |
5x4 =
20 u |
12x4 =
48 u |
7x4 =
28 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of chikoos and grapefruits at first and in the end remains unchanged.
Make the difference in the number of chikoos and grapefruits the same. LCM of 4 and 7 is 28.
Increase in the number of chikoos
= 20 u - 7 u
= 13 u
13 u = 39
1 u = 39 ÷ 13 = 3
Number of grapefruits and chikoos that Paul had at first
= 7 u + 35 u
= 42 u
= 42 x 3
= 126
Answer(s): 126
