Eric bought some pears and chikoos in the ratio of 2 : 5 . After buying another 136 fruits each, the ratio becomes 7 : 9. Find the number of pears and chikoos he has now.
| |
Pears |
Chikoos |
Difference |
| Before |
2x2 =
4 u |
5x2 =
10 u |
3x2 =
6 u |
| Change |
+ 136 |
+ 136 |
|
| After |
7x3 =
21 u |
9x3 =
27 u |
2x3 =
6 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of pears and chikoos at first and in the end remains unchanged.
Make the difference in the number of pears and chikoos the same. LCM of 3 and 2 is 6.
Increase in the number of pears
= 21 u - 4 u
= 17 u
17 u = 136
1 u = 136 ÷ 17 = 8
Number of chikoos and pears that $(Fred) has now
= 21 u + 27 u
= 48 u
= 48 x 8
= 384
Answer(s): 384
