Howard bought some guavas and persimmons in the ratio of 1 : 5 . After buying another 56 fruits each, the ratio becomes 5 : 11. Find the number of guavas and persimmons he has now.
| |
Guavas |
Persimmons |
Difference |
| Before |
1x3 =
3 u |
5x3 =
15 u |
4x3 =
12 u |
| Change |
+ 56 |
+ 56 |
|
| After |
5x2 =
10 u |
11x2 =
22 u |
6x2 =
12 u |
Since the same number of fruits bought for each type of fruits is the same, the difference in the number of guavas and persimmons at first and in the end remains unchanged.
Make the difference in the number of guavas and persimmons the same. LCM of 4 and 6 is 12.
Increase in the number of guavas
= 10 u - 3 u
= 7 u
7 u = 56
1 u = 56 ÷ 7 = 8
Number of persimmons and guavas that $(Fred) has now
= 10 u + 22 u
= 32 u
= 32 x 8
= 256
Answer(s): 256
