Betty has 2 times as many croissants as Opal. The total number of Betty's and Opal's croissants is 4 times of Jean's. Betty and Opal have 18 croissants more than Jean's. How many less croissants does Jean have than Betty?
| Betty |
Opal |
Jean |
| 2x4 |
1x4 |
|
| 4x3 |
1x3 |
| 8 u |
4 u |
3 u |
The total number of croissants that Betty and Opal have is repeated. Make the total number of croissants that Betty and Opal have the same. LCM of 3 and 4 is 12.
Total number of croissants that Betty and Opal have
= 8 u + 4 u
= 12 u
Number of more croissants that Betty and Opal have than Jean
= 12 u - 3 u
= 9 u
9 u = 18
1 u = 18 ÷ 9 = 2
Number of less croissants that Jean has than Betty
= 8 u - 3 u
= 5 u
= 5 x 2
= 10
Answer(s): 10
