Cathy has 3 times as many croissants as Xylia. The total number of Cathy's and Xylia's croissants is 2 times of Risa's. Cathy and Xylia have 16 croissants more than Risa's. How many more croissants does Cathy have than Xylia?
| Cathy |
Xylia |
Risa |
| 3x1 |
1x1 |
|
| 2x2 |
1x2 |
| 3 u |
1 u |
2 u |
The total number of croissants that Cathy and Xylia have is repeated. Make the total number of croissants that Cathy and Xylia have the same. LCM of 4 and 2 is 4.
Total number of croissants that Cathy and Xylia have
= 3 u + 1 u
= 4 u
Number of more croissants that Cathy and Xylia have than Risa
= 4 u - 2 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of more croissants that Cathy has than Xylia
= 3 u - 1 u
= 2 u
= 2 x 8
= 16
Answer(s): 16
