Jane has 6 times as many croissants as Julie. The total number of Jane's and Julie's croissants is 2 times of Fanny's. Jane and Julie have 63 croissants more than Fanny's. How many more croissants does Jane have than Julie?
| Jane |
Julie |
Fanny |
| 6x2 |
1x2 |
|
| 2x7 |
1x7 |
| 12 u |
2 u |
7 u |
The total number of croissants that Jane and Julie have is repeated. Make the total number of croissants that Jane and Julie have the same. LCM of 7 and 2 is 14.
Total number of croissants that Jane and Julie have
= 12 u + 2 u
= 14 u
Number of more croissants that Jane and Julie have than Fanny
= 14 u - 7 u
= 7 u
7 u = 63
1 u = 63 ÷ 7 = 9
Number of more croissants that Jane has than Julie
= 12 u - 2 u
= 10 u
= 10 x 9
= 90
Answer(s): 90
