Shiyun has 6 times as many scones as Julie. The total number of Shiyun's and Julie's scones is 3 times of Jean's. Shiyun and Julie have 98 scones more than Jean's. How many less scones does Jean have than Shiyun?
| Shiyun |
Julie |
Jean |
| 6x3 |
1x3 |
|
| 3x7 |
1x7 |
| 18 u |
3 u |
7 u |
The total number of scones that Shiyun and Julie have is repeated. Make the total number of scones that Shiyun and Julie have the same. LCM of 7 and 3 is 21.
Total number of scones that Shiyun and Julie have
= 18 u + 3 u
= 21 u
Number of more scones that Shiyun and Julie have than Jean
= 21 u - 7 u
= 14 u
14 u = 98
1 u = 98 ÷ 14 = 7
Number of less scones that Jean has than Shiyun
= 18 u - 7 u
= 11 u
= 11 x 7
= 77
Answer(s): 77
