Kathy has 4 times as many shortbreads as Jaslyn. The total number of Kathy's and Jaslyn's shortbreads is 4 times of Jean's. Kathy and Jaslyn have 165 shortbreads more than Jean's. How many less shortbreads does Jean have than Kathy?
| Kathy |
Jaslyn |
Jean |
| 4x4 |
1x4 |
|
| 4x5 |
1x5 |
| 16 u |
4 u |
5 u |
The total number of shortbreads that Kathy and Jaslyn have is repeated. Make the total number of shortbreads that Kathy and Jaslyn have the same. LCM of 5 and 4 is 20.
Total number of shortbreads that Kathy and Jaslyn have
= 16 u + 4 u
= 20 u
Number of more shortbreads that Kathy and Jaslyn have than Jean
= 20 u - 5 u
= 15 u
15 u = 165
1 u = 165 ÷ 15 = 11
Number of less shortbreads that Jean has than Kathy
= 16 u - 5 u
= 11 u
= 11 x 11
= 121
Answer(s): 121
