Gwen has 3 times as many croissants as Xylia. The total number of Gwen's and Xylia's croissants is 2 times of Erika's. Gwen and Xylia have 8 croissants more than Erika's. How many more croissants does Gwen have than Xylia?
| Gwen |
Xylia |
Erika |
| 3x1 |
1x1 |
|
| 2x2 |
1x2 |
| 3 u |
1 u |
2 u |
The total number of croissants that Gwen and Xylia have is repeated. Make the total number of croissants that Gwen and Xylia have the same. LCM of 4 and 2 is 4.
Total number of croissants that Gwen and Xylia have
= 3 u + 1 u
= 4 u
Number of more croissants that Gwen and Xylia have than Erika
= 4 u - 2 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Number of more croissants that Gwen has than Xylia
= 3 u - 1 u
= 2 u
= 2 x 4
= 8
Answer(s): 8
