Eva has 5 times as many biscuits as Kimberly. The total number of Eva's and Kimberly's biscuits is 4 times of Cathy's. Eva and Kimberly have 108 biscuits more than Cathy's. How many more biscuits does Eva have than Kimberly?
| Eva |
Kimberly |
Cathy |
| 5x2 |
1x2 |
|
| 4x3 |
1x3 |
| 10 u |
2 u |
3 u |
The total number of biscuits that Eva and Kimberly have is repeated. Make the total number of biscuits that Eva and Kimberly have the same. LCM of 6 and 4 is 12.
Total number of biscuits that Eva and Kimberly have
= 10 u + 2 u
= 12 u
Number of more biscuits that Eva and Kimberly have than Cathy
= 12 u - 3 u
= 9 u
9 u = 108
1 u = 108 ÷ 9 = 12
Number of more biscuits that Eva has than Kimberly
= 10 u - 2 u
= 8 u
= 8 x 12
= 96
Answer(s): 96
