Dana has 3 times as many shortbreads as Sabrina. The total number of Dana's and Sabrina's shortbreads is 5 times of Kimberly's. Dana and Sabrina have 144 shortbreads more than Kimberly's. How many less shortbreads does Kimberly have than Dana?
| Dana |
Sabrina |
Kimberly |
| 3x5 |
1x5 |
|
| 5x4 |
1x4 |
| 15 u |
5 u |
4 u |
The total number of shortbreads that Dana and Sabrina have is repeated. Make the total number of shortbreads that Dana and Sabrina have the same. LCM of 4 and 5 is 20.
Total number of shortbreads that Dana and Sabrina have
= 15 u + 5 u
= 20 u
Number of more shortbreads that Dana and Sabrina have than Kimberly
= 20 u - 4 u
= 16 u
16 u = 144
1 u = 144 ÷ 16 = 9
Number of less shortbreads that Kimberly has than Dana
= 15 u - 4 u
= 11 u
= 11 x 9
= 99
Answer(s): 99
