Penelope has 2 times as many croissants as Jane. The total number of Penelope's and Jane's croissants is 6 times of Wendy's. Penelope and Jane have 25 croissants more than Wendy's. How many more croissants does Penelope have than Jane?
| Penelope |
Jane |
Wendy |
| 2x2 |
1x2 |
|
| 6x1 |
1x1 |
| 4 u |
2 u |
1 u |
The total number of croissants that Penelope and Jane have is repeated. Make the total number of croissants that Penelope and Jane have the same. LCM of 3 and 6 is 6.
Total number of croissants that Penelope and Jane have
= 4 u + 2 u
= 6 u
Number of more croissants that Penelope and Jane have than Wendy
= 6 u - 1 u
= 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Number of more croissants that Penelope has than Jane
= 4 u - 2 u
= 2 u
= 2 x 5
= 10
Answer(s): 10
