Xylia has 6 times as many croissants as Kathy. The total number of Xylia's and Kathy's croissants is 5 times of Abi's. Xylia and Kathy have 336 croissants more than Abi's. How many less croissants does Abi have than Xylia?
| Xylia |
Kathy |
Abi |
| 6x5 |
1x5 |
|
| 5x7 |
1x7 |
| 30 u |
5 u |
7 u |
The total number of croissants that Xylia and Kathy have is repeated. Make the total number of croissants that Xylia and Kathy have the same. LCM of 7 and 5 is 35.
Total number of croissants that Xylia and Kathy have
= 30 u + 5 u
= 35 u
Number of more croissants that Xylia and Kathy have than Abi
= 35 u - 7 u
= 28 u
28 u = 336
1 u = 336 ÷ 28 = 12
Number of less croissants that Abi has than Xylia
= 30 u - 7 u
= 23 u
= 23 x 12
= 276
Answer(s): 276
