Linda had four boxes, B, C, D and E which contained a total of 223 chikoos. She transferred 26 chikoos from Box B to Box C, 49 chikoos from Box C to Box D and 49 chikoos from Box D to Box E. The ratio of the number of chikoos in Box B to Box C to Box D changed from 4 : 7 : 10 to 1 : 4 : 9. How many chikoos were in Box E at first?
|
Make p the same (1)x4 = (3) |
B (1) |
C (2) |
D
|
E
|
Before |
16 u |
4 u |
7 u |
10 u |
? |
Change 1 |
- 104 |
- 26 |
+ 26 |
|
|
Change 2 |
|
|
- 49 |
+ 49 |
|
Change 3 |
|
|
|
- 49 |
+ 49 |
After |
4 p |
1 p |
4 p |
9 p |
? |
4 u - 26 = 1 p --- (1)
7 u + 26 - 49 = 4 p
7 u - 23 =
4 p --- (2)
(1)
x 4 16 u - 104 =
4 p --- (3)
Make p the same.
(3) = (2)
16 u - 104 = 7 u - 23
16 u - 7 u = 104 - 23
9 u = 81
1 u = 81 ÷ 9 = 9
Total number of chikoos in Box B, Box C and Box D
= 4 u + 7 u + 10 u
= 21 u
Total number of chikoos in Box E at first
= 223 - 21 u
= 223 - 21 x 9
= 223 - 189
= 34
Answer(s): 34