Shannon had four boxes, F, G, H and J which contained a total of 282 pomegranates. She transferred 31 pomegranates from Box F to Box G, 57 pomegranates from Box G to Box H and 120 pomegranates from Box H to Box J. The ratio of the number of pomegranates in Box F to Box G to Box H changed from 3 : 5 : 10 to 1 : 4 : 7. How many pomegranates were in Box J at first?
|
Make p the same (1)x4 = (3) |
F (1) |
G (2) |
H
|
J
|
Before |
12 u |
3 u |
5 u |
10 u |
? |
Change 1 |
- 124 |
- 31 |
+ 31 |
|
|
Change 2 |
|
|
- 57 |
+ 57 |
|
Change 3 |
|
|
|
- 120 |
+ 120 |
After |
4 p |
1 p |
4 p |
7 p |
? |
3 u - 31 = 1 p --- (1)
5 u + 31 - 57 = 4 p
5 u - 26 =
4 p --- (2)
(1)
x 4 12 u - 124 =
4 p --- (3)
Make p the same.
(3) = (2)
12 u - 124 = 5 u - 26
12 u - 5 u = 124 - 26
7 u = 98
1 u = 98 ÷ 7 = 14
Total number of pomegranates in Box F, Box G and Box H
= 3 u + 5 u + 10 u
= 18 u
Total number of pomegranates in Box J at first
= 282 - 18 u
= 282 - 18 x 14
= 282 - 252
= 30
Answer(s): 30