Emily had four boxes, P, Q, R and S which contained a total of 260 persimmons. She transferred 18 persimmons from Box P to Box Q, 45 persimmons from Box Q to Box R and 72 persimmons from Box R to Box S. The ratio of the number of persimmons in Box P to Box Q to Box R changed from 3 : 7 : 10 to 1 : 4 : 7. How many persimmons were in Box S at first?
|
Make p the same (1)x4 = (3) |
P (1) |
Q (2) |
R
|
S
|
Before |
12 u |
3 u |
7 u |
10 u |
? |
Change 1 |
- 72 |
- 18 |
+ 18 |
|
|
Change 2 |
|
|
- 45 |
+ 45 |
|
Change 3 |
|
|
|
- 72 |
+ 72 |
After |
4 p |
1 p |
4 p |
7 p |
? |
3 u - 18 = 1 p --- (1)
7 u + 18 - 45 = 4 p
7 u - 27 =
4 p --- (2)
(1)
x 4 12 u - 72 =
4 p --- (3)
Make p the same.
(3) = (2)
12 u - 72 = 7 u - 27
12 u - 7 u = 72 - 27
5 u = 45
1 u = 45 ÷ 5 = 9
Total number of persimmons in Box P, Box Q and Box R
= 3 u + 7 u + 10 u
= 20 u
Total number of persimmons in Box S at first
= 260 - 20 u
= 260 - 20 x 9
= 260 - 180
= 80
Answer(s): 80