Penelope had four boxes, U, V, W and X which contained a total of 235 kiwis. She transferred 37 kiwis from Box U to Box V, 75 kiwis from Box V to Box W and 164 kiwis from Box W to Box X. The ratio of the number of kiwis in Box U to Box V to Box W changed from 4 : 5 : 11 to 1 : 4 : 7. How many kiwis were in Box X at first?
|
Make p the same (1)x4 = (3) |
U (1) |
V (2) |
W
|
X
|
Before |
16 u |
4 u |
5 u |
11 u |
? |
Change 1 |
- 148 |
- 37 |
+ 37 |
|
|
Change 2 |
|
|
- 75 |
+ 75 |
|
Change 3 |
|
|
|
- 164 |
+ 164 |
After |
4 p |
1 p |
4 p |
7 p |
? |
4 u - 37 = 1 p --- (1)
5 u + 37 - 75 = 4 p
5 u - 38 =
4 p --- (2)
(1)
x 4 16 u - 148 =
4 p --- (3)
Make p the same.
(3) = (2)
16 u - 148 = 5 u - 38
16 u - 5 u = 148 - 38
11 u = 110
1 u = 110 ÷ 11 = 10
Total number of kiwis in Box U, Box V and Box W
= 4 u + 5 u + 11 u
= 20 u
Total number of kiwis in Box X at first
= 235 - 20 u
= 235 - 20 x 10
= 235 - 200
= 35
Answer(s): 35