Risa had four containers, U, V, W and X which contained a total of 316 lemons. She transferred 41 lemons from Container U to Container V, 76 lemons from Container V to Container W and 169 lemons from Container W to Container X. The ratio of the number of lemons in Container U to Container V to Container W changed from 3 : 5 : 9 to 1 : 5 : 6. How many lemons were in Container X at first?
|
Make p the same (1)x5 = (3) |
U (1) |
V (2) |
W
|
X
|
Before |
15 u |
3 u |
5 u |
9 u |
? |
Change 1 |
- 205 |
- 41 |
+ 41 |
|
|
Change 2 |
|
|
- 76 |
+ 76 |
|
Change 3 |
|
|
|
- 169 |
+ 169 |
After |
5 p |
1 p |
5 p |
6 p |
? |
3 u - 41 = 1 p --- (1)
5 u + 41 - 76 = 5 p
5 u - 35 =
5 p --- (2)
(1)
x 5 15 u - 205 =
5 p --- (3)
Make p the same.
(3) = (2)
15 u - 205 = 5 u - 35
15 u - 5 u = 205 - 35
10 u = 170
1 u = 170 ÷ 10 = 17
Total number of lemons in Container U, Container V and Container W
= 3 u + 5 u + 9 u
= 17 u
Total number of lemons in Container X at first
= 316 - 17 u
= 316 - 17 x 17
= 316 - 289
= 27
Answer(s): 27