Opal had four boxes, K, L, M and N which contained a total of 223 apples. She transferred 22 apples from Box K to Box L, 56 apples from Box L to Box M and 125 apples from Box M to Box N. The ratio of the number of apples in Box K to Box L to Box M changed from 3 : 6 : 11 to 1 : 4 : 6. How many apples were in Box N at first?
|
Make p the same (1)x4 = (3) |
K (1) |
L (2) |
M
|
N
|
Before |
12 u |
3 u |
6 u |
11 u |
? |
Change 1 |
- 88 |
- 22 |
+ 22 |
|
|
Change 2 |
|
|
- 56 |
+ 56 |
|
Change 3 |
|
|
|
- 125 |
+ 125 |
After |
4 p |
1 p |
4 p |
6 p |
? |
3 u - 22 = 1 p --- (1)
6 u + 22 - 56 = 4 p
6 u - 34 =
4 p --- (2)
(1)
x 4 12 u - 88 =
4 p --- (3)
Make p the same.
(3) = (2)
12 u - 88 = 6 u - 34
12 u - 6 u = 88 - 34
6 u = 54
1 u = 54 ÷ 6 = 9
Total number of apples in Box K, Box L and Box M
= 3 u + 6 u + 11 u
= 20 u
Total number of apples in Box N at first
= 223 - 20 u
= 223 - 20 x 9
= 223 - 180
= 43
Answer(s): 43