Opal had four boxes, P, Q, R and S which contained a total of 221 apples. She transferred 22 apples from Box P to Box Q, 54 apples from Box Q to Box R and 96 apples from Box R to Box S. The ratio of the number of apples in Box P to Box Q to Box R changed from 4 : 7 : 10 to 1 : 5 : 9. How many apples were in Box S at first?
|
Make p the same (1)x5 = (3) |
P (1) |
Q (2) |
R
|
S
|
Before |
20 u |
4 u |
7 u |
10 u |
? |
Change 1 |
- 110 |
- 22 |
+ 22 |
|
|
Change 2 |
|
|
- 54 |
+ 54 |
|
Change 3 |
|
|
|
- 96 |
+ 96 |
After |
5 p |
1 p |
5 p |
9 p |
? |
4 u - 22 = 1 p --- (1)
7 u + 22 - 54 = 5 p
7 u - 32 =
5 p --- (2)
(1)
x 5 20 u - 110 =
5 p --- (3)
Make p the same.
(3) = (2)
20 u - 110 = 7 u - 32
20 u - 7 u = 110 - 32
13 u = 78
1 u = 78 ÷ 13 = 6
Total number of apples in Box P, Box Q and Box R
= 4 u + 7 u + 10 u
= 21 u
Total number of apples in Box S at first
= 221 - 21 u
= 221 - 21 x 6
= 221 - 126
= 95
Answer(s): 95