Eva had four containers, C, D, E and F which contained a total of 201 kiwis. She transferred 20 kiwis from Container C to Container D, 46 kiwis from Container D to Container E and 59 kiwis from Container E to Container F. The ratio of the number of kiwis in Container C to Container D to Container E changed from 4 : 6 : 11 to 1 : 2 : 8. How many kiwis were in Container F at first?
| |
Make p the same
(1)x2 = (3) |
C
(1) |
D
(2) |
E
|
F
|
| Before |
8 u |
4 u |
6 u |
11 u |
? |
| Change 1 |
- 40 |
- 20 |
+ 20 |
|
|
| Change 2 |
|
|
- 46 |
+ 46 |
|
| Change 3 |
|
|
|
- 59 |
+ 59 |
| After |
2 p |
1 p |
2 p |
8 p |
? |
4 u - 20 = 1 p --- (1)
6 u + 20 - 46 = 2 p
6 u - 26 =
2 p --- (2)
(1)
x 2 8 u - 40 =
2 p --- (3)
Make p the same.
(3) = (2)
8 u - 40 = 6 u - 26
8 u - 6 u = 40 - 26
2 u = 14
1 u = 14 ÷ 2 = 7
Total number of kiwis in Container C, Container D and Container E
= 4 u + 6 u + 11 u
= 21 u
Total number of kiwis in Container F at first
= 201 - 21 u
= 201 - 21 x 7
= 201 - 147
= 54
Answer(s): 54
