Penelope had four boxes, A, B, C and D which contained a total of 260 pears. She transferred 12 pears from Box A to Box B, 15 pears from Box B to Box C and 9 pears from Box C to Box D. The ratio of the number of pears in Box A to Box B to Box C changed from 1 : 2 : 3 to 1 : 5 : 9. How many pears were in Box D at first?
|
Make p the same (1)x5 = (3) |
A (1) |
B (2) |
C
|
D
|
Before |
5 u |
1 u |
2 u |
3 u |
? |
Change 1 |
- 60 |
- 12 |
+ 12 |
|
|
Change 2 |
|
|
- 15 |
+ 15 |
|
Change 3 |
|
|
|
- 9 |
+ 9 |
After |
5 p |
1 p |
5 p |
9 p |
? |
1 u - 12 = 1 p --- (1)
2 u + 12 - 15 = 5 p
2 u - 3 =
5 p --- (2)
(1)
x 5 5 u - 60 =
5 p --- (3)
Make p the same.
(3) = (2)
5 u - 60 = 2 u - 3
5 u - 2 u = 60 - 3
3 u = 57
1 u = 57 ÷ 3 = 19
Total number of pears in Box A, Box B and Box C
= 1 u + 2 u + 3 u
= 6 u
Total number of pears in Box D at first
= 260 - 6 u
= 260 - 6 x 19
= 260 - 114
= 146
Answer(s): 146