Irene had four boxes, L, M, N and P which contained a total of 204 starfruits. She transferred 19 starfruits from Box L to Box M, 29 starfruits from Box M to Box N and 48 starfruits from Box N to Box P. The ratio of the number of starfruits in Box L to Box M to Box N changed from 4 : 5 : 9 to 1 : 4 : 7. How many starfruits were in Box P at first?
|
Make p the same (1)x4 = (3) |
L (1) |
M (2) |
N
|
P
|
Before |
16 u |
4 u |
5 u |
9 u |
? |
Change 1 |
- 76 |
- 19 |
+ 19 |
|
|
Change 2 |
|
|
- 29 |
+ 29 |
|
Change 3 |
|
|
|
- 48 |
+ 48 |
After |
4 p |
1 p |
4 p |
7 p |
? |
4 u - 19 = 1 p --- (1)
5 u + 19 - 29 = 4 p
5 u - 10 =
4 p --- (2)
(1)
x 4 16 u - 76 =
4 p --- (3)
Make p the same.
(3) = (2)
16 u - 76 = 5 u - 10
16 u - 5 u = 76 - 10
11 u = 66
1 u = 66 ÷ 11 = 6
Total number of starfruits in Box L, Box M and Box N
= 4 u + 5 u + 9 u
= 18 u
Total number of starfruits in Box P at first
= 204 - 18 u
= 204 - 18 x 6
= 204 - 108
= 96
Answer(s): 96