Natalie had four boxes, N, P, Q and R which contained a total of 266 pears. She transferred 36 pears from Box N to Box P, 89 pears from Box P to Box Q and 143 pears from Box Q to Box R. The ratio of the number of pears in Box N to Box P to Box Q changed from 4 : 7 : 10 to 1 : 3 : 7. How many pears were in Box R at first?
|
Make p the same (1)x3 = (3) |
N (1) |
P (2) |
Q
|
R
|
Before |
12 u |
4 u |
7 u |
10 u |
? |
Change 1 |
- 108 |
- 36 |
+ 36 |
|
|
Change 2 |
|
|
- 89 |
+ 89 |
|
Change 3 |
|
|
|
- 143 |
+ 143 |
After |
3 p |
1 p |
3 p |
7 p |
? |
4 u - 36 = 1 p --- (1)
7 u + 36 - 89 = 3 p
7 u - 53 =
3 p --- (2)
(1)
x 3 12 u - 108 =
3 p --- (3)
Make p the same.
(3) = (2)
12 u - 108 = 7 u - 53
12 u - 7 u = 108 - 53
5 u = 55
1 u = 55 ÷ 5 = 11
Total number of pears in Box N, Box P and Box Q
= 4 u + 7 u + 10 u
= 21 u
Total number of pears in Box R at first
= 266 - 21 u
= 266 - 21 x 11
= 266 - 231
= 35
Answer(s): 35