The number of boys to the number of girls in Primary 4 Patience was 2 : 5. The number of boys to the number of girls in Primary 4 Faithfulness was 3 : 5. Both classes had the same number of boys. When 10 girls from Primary 4 Patience joined Primary 4 Faithfulness, the ratio of the number of boys to the number of girls in Primary 4 Patience became 3 : 5. Find the total enrolment of both classes.
Primary 4 Patience |
Primary 4 Faithfulness |
Boys |
Girls |
Boys |
Girls |
2x3 |
5x3 |
3x2 |
5x2 |
1x6 |
|
1x6 |
|
6 u |
15 u |
6 u |
10 u |
The number of boys in both classes is the same. Make the number of boys the same. LCM of 2 and 3 is 6.
|
Primary 4 Patience |
Primary 4 Faithfulness |
|
Boys |
Girls |
Boys |
Girls |
Before |
6 u |
15 u |
6 u |
10 u |
Change |
|
- 10 |
|
+ 10 |
After |
3x2 = 6 u |
5x2 = 10 u |
6 u |
10 u + 10 |
The number of boys in Primary 4 Patience remains unchanged. Make the number of boys in Primary 4 the same. LCM of 6 and 3 is 6.
Number of girls from Primary 4 Patience that joined Primary 4 Faithfulness
= 15 u - 10 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Total enrolment of both classes
= 6 u + 15 u + 6 u + 10 u
= 37 u
= 37 x 2
= 74
Answer(s): 74