The number of boys to the number of girls in Primary 5 Gentleness was 2 : 5. The number of boys to the number of girls in Primary 5 Patience was 4 : 5. Both classes had the same number of boys. When 10 girls from Primary 5 Gentleness joined Primary 5 Patience, the ratio of the number of boys to the number of girls in Primary 5 Gentleness became 1 : 2. Find the total enrolment of both classes.
Primary 5 Gentleness |
Primary 5 Patience |
Boys |
Girls |
Boys |
Girls |
2x2 |
5x2 |
4x1 |
5x1 |
1x4 |
|
1x4 |
|
4 u |
10 u |
4 u |
5 u |
The number of boys in both classes is the same. Make the number of boys the same. LCM of 2 and 4 is 4.
|
Primary 5 Gentleness |
Primary 5 Patience |
|
Boys |
Girls |
Boys |
Girls |
Before |
4 u |
10 u |
4 u |
5 u |
Change |
|
- 10 |
|
+ 10 |
After |
1x4 = 4 u |
2x4 = 8 u |
4 u |
5 u + 10 |
The number of boys in Primary 5 Gentleness remains unchanged. Make the number of boys in Primary 5 the same. LCM of 4 and 1 is 4.
Number of girls from Primary 5 Gentleness that joined Primary 5 Patience
= 10 u - 8 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Total enrolment of both classes
= 4 u + 10 u + 4 u + 5 u
= 23 u
= 23 x 5
= 115
Answer(s): 115