The number of boys to the number of girls in Primary 5 Gentleness was 3 : 5. The number of boys to the number of girls in Primary 5 Patience was 4 : 5. Both classes had the same number of boys. When 12 girls from Primary 5 Gentleness joined Primary 5 Patience, the ratio of the number of boys to the number of girls in Primary 5 Gentleness became 6 : 7. Find the total enrolment of both classes.
Primary 5 Gentleness |
Primary 5 Patience |
Boys |
Girls |
Boys |
Girls |
3x4 |
5x4 |
4x3 |
5x3 |
1x12 |
|
1x12 |
|
12 u |
20 u |
12 u |
15 u |
The number of boys in both classes is the same. Make the number of boys the same. LCM of 3 and 4 is 12.
|
Primary 5 Gentleness |
Primary 5 Patience |
|
Boys |
Girls |
Boys |
Girls |
Before |
12 u |
20 u |
12 u |
15 u |
Change |
|
- 12 |
|
+ 12 |
After |
6x2 = 12 u |
7x2 = 14 u |
12 u |
15 u + 12 |
The number of boys in Primary 5 Gentleness remains unchanged. Make the number of boys in Primary 5 the same. LCM of 12 and 6 is 12.
Number of girls from Primary 5 Gentleness that joined Primary 5 Patience
= 20 u - 14 u
= 6 u
6 u = 12
1 u = 12 ÷ 6 = 2
Total enrolment of both classes
= 12 u + 20 u + 12 u + 15 u
= 59 u
= 59 x 2
= 118
Answer(s): 118