There were some starfruits and persimmons in Container D and Container E. In Container D, the ratio of the starfruits to the number of persimmons was 6 : 1. In Container E, the ratio of the number of starfruits to the number of persimmons was 4 : 3. There were 3 times as many fruits in Container D as in Container E. After another 90 persimmons were put into Container E, the ratio of the number of starfruits to the number of persimmons in Container E became 1 : 3. How many fruits were there in Container D?

Container D		Container E
3x7 = 21 u		1x7 = 7 u
Starfruits	Persimmons	Starfruits	Persimmons
6x3	1x3	4	3
18 u	3 u	4 u	3 u

The total number of fruits in Container D is repeated.  Make the total number of fruits in Container D the same.  LCM of 3 and 7 is 21.

The total number of fruits in Container E at first is repeated.  Make the total number of fruits in Container E the same.  LCM of 1 and 7 is 7.

	Container D		Container E
	Starfruits	Persimmons	Starfruits	Persimmons
Before	18 u	3 u	4 u	3 u
Change				+ 90
After	18 u	3 u	1x4 = 4 u	3x4 = 12 u

Number of starfruits in Container E remains unchanged.  Make the number of starfruits in Container E the same.  LCM of 4 and 1 is 4.

Number of persimmons put into Container E
= 12 u - 3 u
= 9 u

9 u = 90

1 u = 90 ÷ 9 = 10

Number of fruits in Container D
= 18 u + 3 u
= 21 u
= 21 x 10
= 210

Answer(s): 210