There were some pears and persimmons in Box G and Box H. In Box G, the ratio of the pears to the number of persimmons was 6 : 1. In Box H, the ratio of the number of pears to the number of persimmons was 5 : 2. There were 3 times as many fruits in Box G as in Box H. After another 64 persimmons were put into Box H, the ratio of the number of pears to the number of persimmons in Box H became 1 : 2. How many fruits were there in Box H in the end?

Box G		Box H
3x7 = 21 u		1x7 = 7 u
Pears	Persimmons	Pears	Persimmons
6x3	1x3	5	2
18 u	3 u	5 u	2 u

The total number of fruits in Box G is repeated.  Make the total number of fruits in Box G the same.  LCM of 3 and 7 is 21.

The total number of fruits in Box H at first is repeated.  Make the total number of fruits in Box H the same.  LCM of 1 and 7 is 7.

	Box G		Box H
	Pears	Persimmons	Pears	Persimmons
Before	18 u	3 u	5 u	2 u
Change				+ 64
After	18 u	3 u	1x5 = 5 u	2x5 = 10 u

Number of pears in Box H remains unchanged.  Make the number of pears in Box H the same.  LCM of 5 and 1 is 5.

Number of persimmons put into Box H
= 10 u - 2 u
= 8 u

8 u = 64

1 u = 64 ÷ 8 = 8

Number of fruits in Box H in the end
= 5 u + 10 u
= 15 u
= 15 x 8
= 120

Answer(s): 120