There were some pears and starfruits in Box G and Box H. In Box G, the ratio of the pears to the number of starfruits was 7 : 1. In Box H, the ratio of the number of pears to the number of starfruits was 5 : 3. There were 3 times as many fruits in Box G as in Box H. After another 120 starfruits were put into Box H, the ratio of the number of pears to the number of starfruits in Box H became 1 : 3. How many fruits were there in Box G?
Box G |
Box H |
3x8 = 24 u |
1x8 = 8 u |
Pears |
Starfruits |
Pears |
Starfruits |
7x3 |
1x3 |
5 |
3 |
21 u |
3 u |
5 u |
3 u |
The total number of fruits in Box G is repeated. Make the total number of fruits in Box G the same. LCM of 3 and 8 is 24.
The total number of fruits in Box H at first is repeated. Make the total number of fruits in Box H the same. LCM of 1 and 8 is 8.
|
Box G |
Box H |
|
Pears |
Starfruits |
Pears |
Starfruits |
Before |
21 u |
3 u |
5 u |
3 u |
Change |
|
|
|
+ 120 |
After
|
21 u
|
3 u
|
1x5 = 5 u |
3x5 = 15 u |
Number of pears in Box H remains unchanged. Make the number of pears in Box H the same. LCM of 5 and 1 is 5.
Number of starfruits put into Box H
= 15 u - 3 u
= 12 u
12 u = 120
1 u = 120 ÷ 12 = 10
Number of fruits in Box G
= 21 u + 3 u
= 24 u
= 24 x 10
= 240
Answer(s): 240