There were some persimmons and kiwis in Container C and Container D. In Container C, the ratio of the persimmons to the number of kiwis was 6 : 1. In Container D, the ratio of the number of persimmons to the number of kiwis was 4 : 3. There were 3 times as many fruits in Container C as in Container D. After another 65 kiwis were put into Container D, the ratio of the number of persimmons to the number of kiwis in Container D became 1 : 4. How many fruits were there in Container C?

Container C		Container D
3x7 = 21 u		1x7 = 7 u
Persimmons	Kiwis	Persimmons	Kiwis
6x3	1x3	4	3
18 u	3 u	4 u	3 u

The total number of fruits in Container C is repeated.  Make the total number of fruits in Container C the same.  LCM of 3 and 7 is 21.

The total number of fruits in Container D at first is repeated.  Make the total number of fruits in Container D the same.  LCM of 1 and 7 is 7.

	Container C		Container D
	Persimmons	Kiwis	Persimmons	Kiwis
Before	18 u	3 u	4 u	3 u
Change				+ 65
After	18 u	3 u	1x4 = 4 u	4x4 = 16 u

Number of persimmons in Container D remains unchanged.  Make the number of persimmons in Container D the same.  LCM of 4 and 1 is 4.

Number of kiwis put into Container D
= 16 u - 3 u
= 13 u

13 u = 65

1 u = 65 ÷ 13 = 5

Number of fruits in Container C
= 18 u + 3 u
= 21 u
= 21 x 5
= 105

Answer(s): 105