There were some mangosteens and pears in Box T and Box U. In Box T, the ratio of the mangosteens to the number of pears was 4 : 1. In Box U, the ratio of the number of mangosteens to the number of pears was 3 : 2. There were 2 times as many fruits in Box T as in Box U. After another 8 pears were put into Box U, the ratio of the number of mangosteens to the number of pears in Box U became 1 : 2. How many fruits were there in Box T?
Box T |
Box U |
2x5 = 10 u |
1x5 = 5 u |
Mangosteens |
Pears |
Mangosteens |
Pears |
4x2 |
1x2 |
3 |
2 |
8 u |
2 u |
3 u |
2 u |
The total number of fruits in Box T is repeated. Make the total number of fruits in Box T the same. LCM of 2 and 5 is 10.
The total number of fruits in Box U at first is repeated. Make the total number of fruits in Box U the same. LCM of 1 and 5 is 5.
|
Box T |
Box U |
|
Mangosteens |
Pears |
Mangosteens |
Pears |
Before |
8 u |
2 u |
3 u |
2 u |
Change |
|
|
|
+ 8 |
After
|
8 u
|
2 u
|
1x3 = 3 u |
2x3 = 6 u |
Number of mangosteens in Box U remains unchanged. Make the number of mangosteens in Box U the same. LCM of 3 and 1 is 3.
Number of pears put into Box U
= 6 u - 2 u
= 4 u
4 u = 8
1 u = 8 ÷ 4 = 2
Number of fruits in Box T
= 8 u + 2 u
= 10 u
= 10 x 2
= 20
Answer(s): 20