There were some apples and kiwis in Box N and Box P. In Box N, the ratio of the apples to the number of kiwis was 3 : 1. In Box P, the ratio of the number of apples to the number of kiwis was 3 : 1. There were 3 times as many fruits in Box N as in Box P. After another 25 kiwis were put into Box P, the ratio of the number of apples to the number of kiwis in Box P became 1 : 2. How many fruits were there in Box N?

Box N		Box P
3x4 = 12 u		1x4 = 4 u
Apples	Kiwis	Apples	Kiwis
3x3	1x3	3	1
9 u	3 u	3 u	1 u

The total number of fruits in Box N is repeated.  Make the total number of fruits in Box N the same.  LCM of 3 and 4 is 12.

The total number of fruits in Box P at first is repeated.  Make the total number of fruits in Box P the same.  LCM of 1 and 4 is 4.

	Box N		Box P
	Apples	Kiwis	Apples	Kiwis
Before	9 u	3 u	3 u	1 u
Change				+ 25
After	9 u	3 u	1x3 = 3 u	2x3 = 6 u

Number of apples in Box P remains unchanged.  Make the number of apples in Box P the same.  LCM of 3 and 1 is 3.

Number of kiwis put into Box P
= 6 u - 1 u
= 5 u

5 u = 25

1 u = 25 ÷ 5 = 5

Number of fruits in Box N
= 9 u + 3 u
= 12 u
= 12 x 5
= 60

Answer(s): 60