There were some mangoes and mangosteens in Container V and Container W. In Container V, the ratio of the mangoes to the number of mangosteens was 7 : 1. In Container W, the ratio of the number of mangoes to the number of mangosteens was 5 : 3. There were 2 times as many fruits in Container V as in Container W. After another 51 mangosteens were put into Container W, the ratio of the number of mangoes to the number of mangosteens in Container W became 1 : 4. How many fruits were there in Container W in the end?
Container V |
Container W |
2x8 = 16 u |
1x8 = 8 u |
Mangoes |
Mangosteens |
Mangoes |
Mangosteens |
7x2 |
1x2 |
5 |
3 |
14 u |
2 u |
5 u |
3 u |
The total number of fruits in Container V is repeated. Make the total number of fruits in Container V the same. LCM of 2 and 8 is 16.
The total number of fruits in Container W at first is repeated. Make the total number of fruits in Container W the same. LCM of 1 and 8 is 8.
|
Container V |
Container W |
|
Mangoes |
Mangosteens |
Mangoes |
Mangosteens |
Before |
14 u |
2 u |
5 u |
3 u |
Change |
|
|
|
+ 51 |
After
|
14 u
|
2 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of mangoes in Container W remains unchanged. Make the number of mangoes in Container W the same. LCM of 5 and 1 is 5.
Number of mangosteens put into Container W
= 20 u - 3 u
= 17 u
17 u = 51
1 u = 51 ÷ 17 = 3
Number of fruits in Container W in the end
= 5 u + 20 u
= 25 u
= 25 x 3
= 75
Answer(s): 75