There were some pomegranates and mangoes in Container U and Container V. In Container U, the ratio of the pomegranates to the number of mangoes was 7 : 1. In Container V, the ratio of the number of pomegranates to the number of mangoes was 5 : 3. There were 3 times as many fruits in Container U as in Container V. After another 108 mangoes were put into Container V, the ratio of the number of pomegranates to the number of mangoes in Container V became 1 : 3. How many fruits were there in Container U?

Container U		Container V
3x8 = 24 u		1x8 = 8 u
Pomegranates	Mangoes	Pomegranates	Mangoes
7x3	1x3	5	3
21 u	3 u	5 u	3 u

The total number of fruits in Container U is repeated.  Make the total number of fruits in Container U the same.  LCM of 3 and 8 is 24.

The total number of fruits in Container V at first is repeated.  Make the total number of fruits in Container V the same.  LCM of 1 and 8 is 8.

	Container U		Container V
	Pomegranates	Mangoes	Pomegranates	Mangoes
Before	21 u	3 u	5 u	3 u
Change				+ 108
After	21 u	3 u	1x5 = 5 u	3x5 = 15 u

Number of pomegranates in Container V remains unchanged.  Make the number of pomegranates in Container V the same.  LCM of 5 and 1 is 5.

Number of mangoes put into Container V
= 15 u - 3 u
= 12 u

12 u = 108

1 u = 108 ÷ 12 = 9

Number of fruits in Container U
= 21 u + 3 u
= 24 u
= 24 x 9
= 216

Answer(s): 216