There were some oranges and persimmons in Box Y and Box Z. In Box Y, the ratio of the oranges to the number of persimmons was 3 : 1. In Box Z, the ratio of the number of oranges to the number of persimmons was 5 : 3. There were 2 times as many fruits in Box Y as in Box Z. After another 70 persimmons were put into Box Z, the ratio of the number of oranges to the number of persimmons in Box Z became 1 : 2. How many fruits were there in Box Z in the end?

Box Y		Box Z
2x8 = 16 u		1x8 = 8 u
Oranges	Persimmons	Oranges	Persimmons
3x4	1x4	5	3
12 u	4 u	5 u	3 u

The total number of fruits in Box Y is repeated.  Make the total number of fruits in Box Y the same.  LCM of 2 and 4 is 16.

The total number of fruits in Box Z at first is repeated.  Make the total number of fruits in Box Z the same.  LCM of 1 and 8 is 8.

	Box Y		Box Z
	Oranges	Persimmons	Oranges	Persimmons
Before	12 u	4 u	5 u	3 u
Change				+ 70
After	12 u	4 u	1x5 = 5 u	2x5 = 10 u

Number of oranges in Box Z remains unchanged.  Make the number of oranges in Box Z the same.  LCM of 5 and 1 is 5.

Number of persimmons put into Box Z
= 10 u - 3 u
= 7 u

7 u = 70

1 u = 70 ÷ 7 = 10

Number of fruits in Box Z in the end
= 5 u + 10 u
= 15 u
= 15 x 10
= 150

Answer(s): 150