There were some chikoos and passion fruits in Box X and Box Y. In Box X, the ratio of the chikoos to the number of passion fruits was 7 : 1. In Box Y, the ratio of the number of chikoos to the number of passion fruits was 5 : 3. There were 3 times as many fruits in Box X as in Box Y. After another 102 passion fruits were put into Box Y, the ratio of the number of chikoos to the number of passion fruits in Box Y became 1 : 4. How many fruits were there in Box X?
Box X |
Box Y |
3x8 = 24 u |
1x8 = 8 u |
Chikoos |
Passion fruits |
Chikoos |
Passion fruits |
7x3 |
1x3 |
5 |
3 |
21 u |
3 u |
5 u |
3 u |
The total number of fruits in Box X is repeated. Make the total number of fruits in Box X the same. LCM of 3 and 8 is 24.
The total number of fruits in Box Y at first is repeated. Make the total number of fruits in Box Y the same. LCM of 1 and 8 is 8.
|
Box X |
Box Y |
|
Chikoos |
Passion fruits |
Chikoos |
Passion fruits |
Before |
21 u |
3 u |
5 u |
3 u |
Change |
|
|
|
+ 102 |
After
|
21 u
|
3 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of chikoos in Box Y remains unchanged. Make the number of chikoos in Box Y the same. LCM of 5 and 1 is 5.
Number of passion fruits put into Box Y
= 20 u - 3 u
= 17 u
17 u = 102
1 u = 102 ÷ 17 = 6
Number of fruits in Box X
= 21 u + 3 u
= 24 u
= 24 x 6
= 144
Answer(s): 144