There were some mangoes and starfruits in Container E and Container F. In Container E, the ratio of the mangoes to the number of starfruits was 11 : 1. In Container F, the ratio of the number of mangoes to the number of starfruits was 5 : 3. There were 3 times as many fruits in Container E as in Container F. After another 56 starfruits were put into Container F, the ratio of the number of mangoes to the number of starfruits in Container F became 1 : 2. How many fruits were there in Container F in the end?

Container E		Container F
3x8 = 24 u		1x8 = 8 u
Mangoes	Starfruits	Mangoes	Starfruits
11x2	1x2	5	3
22 u	2 u	5 u	3 u

The total number of fruits in Container E is repeated.  Make the total number of fruits in Container E the same.  LCM of 3 and 12 is 24.

The total number of fruits in Container F at first is repeated.  Make the total number of fruits in Container F the same.  LCM of 1 and 8 is 8.

	Container E		Container F
	Mangoes	Starfruits	Mangoes	Starfruits
Before	22 u	2 u	5 u	3 u
Change				+ 56
After	22 u	2 u	1x5 = 5 u	2x5 = 10 u

Number of mangoes in Container F remains unchanged.  Make the number of mangoes in Container F the same.  LCM of 5 and 1 is 5.

Number of starfruits put into Container F
= 10 u - 3 u
= 7 u

7 u = 56

1 u = 56 ÷ 7 = 8

Number of fruits in Container F in the end
= 5 u + 10 u
= 15 u
= 15 x 8
= 120

Answer(s): 120