There were some oranges and apples in Container W and Container X. In Container W, the ratio of the oranges to the number of apples was 3 : 1. In Container X, the ratio of the number of oranges to the number of apples was 5 : 3. There were 2 times as many fruits in Container W as in Container X. After another 153 apples were put into Container X, the ratio of the number of oranges to the number of apples in Container X became 1 : 4. How many fruits were there in Container X in the end?
Container W |
Container X |
2x8 = 16 u |
1x8 = 8 u |
Oranges |
Apples |
Oranges |
Apples |
3x4 |
1x4 |
5 |
3 |
12 u |
4 u |
5 u |
3 u |
The total number of fruits in Container W is repeated. Make the total number of fruits in Container W the same. LCM of 2 and 4 is 16.
The total number of fruits in Container X at first is repeated. Make the total number of fruits in Container X the same. LCM of 1 and 8 is 8.
|
Container W |
Container X |
|
Oranges |
Apples |
Oranges |
Apples |
Before |
12 u |
4 u |
5 u |
3 u |
Change |
|
|
|
+ 153 |
After
|
12 u
|
4 u
|
1x5 = 5 u |
4x5 = 20 u |
Number of oranges in Container X remains unchanged. Make the number of oranges in Container X the same. LCM of 5 and 1 is 5.
Number of apples put into Container X
= 20 u - 3 u
= 17 u
17 u = 153
1 u = 153 ÷ 17 = 9
Number of fruits in Container X in the end
= 5 u + 20 u
= 25 u
= 25 x 9
= 225
Answer(s): 225