There were some pomegranates and pears in Box C and Box D. In Box C, the ratio of the pomegranates to the number of pears was 7 : 1. In Box D, the ratio of the number of pomegranates to the number of pears was 5 : 3. There were 3 times as many fruits in Box C as in Box D. After another 84 pears were put into Box D, the ratio of the number of pomegranates to the number of pears in Box D became 1 : 3. How many fruits were there in Box D in the end?

Box C		Box D
3x8 = 24 u		1x8 = 8 u
Pomegranates	Pears	Pomegranates	Pears
7x3	1x3	5	3
21 u	3 u	5 u	3 u

The total number of fruits in Box C is repeated.  Make the total number of fruits in Box C the same.  LCM of 3 and 8 is 24.

The total number of fruits in Box D at first is repeated.  Make the total number of fruits in Box D the same.  LCM of 1 and 8 is 8.

	Box C		Box D
	Pomegranates	Pears	Pomegranates	Pears
Before	21 u	3 u	5 u	3 u
Change				+ 84
After	21 u	3 u	1x5 = 5 u	3x5 = 15 u

Number of pomegranates in Box D remains unchanged.  Make the number of pomegranates in Box D the same.  LCM of 5 and 1 is 5.

Number of pears put into Box D
= 15 u - 3 u
= 12 u

12 u = 84

1 u = 84 ÷ 12 = 7

Number of fruits in Box D in the end
= 5 u + 15 u
= 20 u
= 20 x 7
= 140

Answer(s): 140