There were some lemons and persimmons in Container N and Container P. In Container N, the ratio of the lemons to the number of persimmons was 6 : 1. In Container P, the ratio of the number of lemons to the number of persimmons was 4 : 3. There were 2 times as many fruits in Container N as in Container P. After another 39 persimmons were put into Container P, the ratio of the number of lemons to the number of persimmons in Container P became 1 : 4. How many fruits were there in Container N?
Container N |
Container P |
2x7 = 14 u |
1x7 = 7 u |
Lemons |
Persimmons |
Lemons |
Persimmons |
6x2 |
1x2 |
4 |
3 |
12 u |
2 u |
4 u |
3 u |
The total number of fruits in Container N is repeated. Make the total number of fruits in Container N the same. LCM of 2 and 7 is 14.
The total number of fruits in Container P at first is repeated. Make the total number of fruits in Container P the same. LCM of 1 and 7 is 7.
|
Container N |
Container P |
|
Lemons |
Persimmons |
Lemons |
Persimmons |
Before |
12 u |
2 u |
4 u |
3 u |
Change |
|
|
|
+ 39 |
After
|
12 u
|
2 u
|
1x4 = 4 u |
4x4 = 16 u |
Number of lemons in Container P remains unchanged. Make the number of lemons in Container P the same. LCM of 4 and 1 is 4.
Number of persimmons put into Container P
= 16 u - 3 u
= 13 u
13 u = 39
1 u = 39 ÷ 13 = 3
Number of fruits in Container N
= 12 u + 2 u
= 14 u
= 14 x 3
= 42
Answer(s): 42