There were some kiwis and pears in Container T and Container U. In Container T, the ratio of the kiwis to the number of pears was 5 : 1. In Container U, the ratio of the number of kiwis to the number of pears was 3 : 1. There were 3 times as many fruits in Container T as in Container U. After another 64 pears were put into Container U, the ratio of the number of kiwis to the number of pears in Container U became 1 : 3. How many fruits were there in Container T?

Container T		Container U
3x4 = 12 u		1x4 = 4 u
Kiwis	Pears	Kiwis	Pears
5x2	1x2	3	1
10 u	2 u	3 u	1 u

The total number of fruits in Container T is repeated.  Make the total number of fruits in Container T the same.  LCM of 3 and 6 is 12.

The total number of fruits in Container U at first is repeated.  Make the total number of fruits in Container U the same.  LCM of 1 and 4 is 4.

	Container T		Container U
	Kiwis	Pears	Kiwis	Pears
Before	10 u	2 u	3 u	1 u
Change				+ 64
After	10 u	2 u	1x3 = 3 u	3x3 = 9 u

Number of kiwis in Container U remains unchanged.  Make the number of kiwis in Container U the same.  LCM of 3 and 1 is 3.

Number of pears put into Container U
= 9 u - 1 u
= 8 u

8 u = 64

1 u = 64 ÷ 8 = 8

Number of fruits in Container T
= 10 u + 2 u
= 12 u
= 12 x 8
= 96

Answer(s): 96