There were some pomegranates and persimmons in Box C and Box D. In Box C, the ratio of the pomegranates to the number of persimmons was 3 : 1. In Box D, the ratio of the number of pomegranates to the number of persimmons was 3 : 1. There were 2 times as many fruits in Box C as in Box D. After another 24 persimmons were put into Box D, the ratio of the number of pomegranates to the number of persimmons in Box D became 1 : 3. How many fruits were there in Box D in the end?

Box C		Box D
2x4 = 8 u		1x4 = 4 u
Pomegranates	Persimmons	Pomegranates	Persimmons
3x2	1x2	3	1
6 u	2 u	3 u	1 u

The total number of fruits in Box C is repeated.  Make the total number of fruits in Box C the same.  LCM of 2 and 4 is 8.

The total number of fruits in Box D at first is repeated.  Make the total number of fruits in Box D the same.  LCM of 1 and 4 is 4.

	Box C		Box D
	Pomegranates	Persimmons	Pomegranates	Persimmons
Before	6 u	2 u	3 u	1 u
Change				+ 24
After	6 u	2 u	1x3 = 3 u	3x3 = 9 u

Number of pomegranates in Box D remains unchanged.  Make the number of pomegranates in Box D the same.  LCM of 3 and 1 is 3.

Number of persimmons put into Box D
= 9 u - 1 u
= 8 u

8 u = 24

1 u = 24 ÷ 8 = 3

Number of fruits in Box D in the end
= 3 u + 9 u
= 12 u
= 12 x 3
= 36

Answer(s): 36