There were some persimmons and kiwis in Container W and Container X. In Container W, the ratio of the persimmons to the number of kiwis was 4 : 1. In Container X, the ratio of the number of persimmons to the number of kiwis was 3 : 2. There were 3 times as many fruits in Container W as in Container X. After another 28 kiwis were put into Container X, the ratio of the number of persimmons to the number of kiwis in Container X became 1 : 3. How many fruits were there in Container X in the end?

Container W		Container X
3x5 = 15 u		1x5 = 5 u
Persimmons	Kiwis	Persimmons	Kiwis
4x3	1x3	3	2
12 u	3 u	3 u	2 u

The total number of fruits in Container W is repeated.  Make the total number of fruits in Container W the same.  LCM of 3 and 5 is 15.

The total number of fruits in Container X at first is repeated.  Make the total number of fruits in Container X the same.  LCM of 1 and 5 is 5.

	Container W		Container X
	Persimmons	Kiwis	Persimmons	Kiwis
Before	12 u	3 u	3 u	2 u
Change				+ 28
After	12 u	3 u	1x3 = 3 u	3x3 = 9 u

Number of persimmons in Container X remains unchanged.  Make the number of persimmons in Container X the same.  LCM of 3 and 1 is 3.

Number of kiwis put into Container X
= 9 u - 2 u
= 7 u

7 u = 28

1 u = 28 ÷ 7 = 4

Number of fruits in Container X in the end
= 3 u + 9 u
= 12 u
= 12 x 4
= 48

Answer(s): 48