There were some oranges and chikoos in Box R and Box S. In Box R, the ratio of the oranges to the number of chikoos was 6 : 1. In Box S, the ratio of the number of oranges to the number of chikoos was 5 : 2. There were 3 times as many fruits in Box R as in Box S. After another 72 chikoos were put into Box S, the ratio of the number of oranges to the number of chikoos in Box S became 1 : 2. How many fruits were there in Box S in the end?

Box R		Box S
3x7 = 21 u		1x7 = 7 u
Oranges	Chikoos	Oranges	Chikoos
6x3	1x3	5	2
18 u	3 u	5 u	2 u

The total number of fruits in Box R is repeated.  Make the total number of fruits in Box R the same.  LCM of 3 and 7 is 21.

The total number of fruits in Box S at first is repeated.  Make the total number of fruits in Box S the same.  LCM of 1 and 7 is 7.

	Box R		Box S
	Oranges	Chikoos	Oranges	Chikoos
Before	18 u	3 u	5 u	2 u
Change				+ 72
After	18 u	3 u	1x5 = 5 u	2x5 = 10 u

Number of oranges in Box S remains unchanged.  Make the number of oranges in Box S the same.  LCM of 5 and 1 is 5.

Number of chikoos put into Box S
= 10 u - 2 u
= 8 u

8 u = 72

1 u = 72 ÷ 8 = 9

Number of fruits in Box S in the end
= 5 u + 10 u
= 15 u
= 15 x 9
= 135

Answer(s): 135